-8x^2+17x+18=0

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Solution for -8x^2+17x+18=0 equation:



-8x^2+17x+18=0
a = -8; b = 17; c = +18;
Δ = b2-4ac
Δ = 172-4·(-8)·18
Δ = 865
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{865}}{2*-8}=\frac{-17-\sqrt{865}}{-16} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{865}}{2*-8}=\frac{-17+\sqrt{865}}{-16} $

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